-4x^2-48x-80=0

Solution for -4x^2-48x-80=0 equation:

-4x^2-48x-80=0

a = -4; b = -48; c = -80;
Δ = b2-4ac
Δ = -482-4·(-4)·(-80)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-32}{2*-4}=\frac{16}{-8}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+32}{2*-4}=\frac{80}{-8}
=-10
$